Which operator should be used to determine if a number is evenly divisible by 5?

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Multiple Choice

Which operator should be used to determine if a number is evenly divisible by 5?

Explanation:
The operator that should be used to determine if a number is evenly divisible by 5 is the modulus operator, represented by the percent sign (%). This operator calculates the remainder of the division of one number by another. When you use the modulus operator with a number and 5, such as `number % 5`, it will return 0 if the number is evenly divisible by 5. This happens because there is no remainder when the division is complete. For example, if you check `15 % 5`, the result is 0, which means that 15 is evenly divisible by 5. Conversely, if you check `14 % 5`, the result is 4, indicating that 14 is not evenly divisible by 5. In contrast, the other operators like addition (+), subtraction (-), and multiplication (*) do not help in determining divisibility. They perform arithmetic operations that do not provide information about remainders in division context. Therefore, using the modulus operator is the correct approach to check for even divisibility by any number, including 5.

The operator that should be used to determine if a number is evenly divisible by 5 is the modulus operator, represented by the percent sign (%). This operator calculates the remainder of the division of one number by another.

When you use the modulus operator with a number and 5, such as number % 5, it will return 0 if the number is evenly divisible by 5. This happens because there is no remainder when the division is complete. For example, if you check 15 % 5, the result is 0, which means that 15 is evenly divisible by 5. Conversely, if you check 14 % 5, the result is 4, indicating that 14 is not evenly divisible by 5.

In contrast, the other operators like addition (+), subtraction (-), and multiplication (*) do not help in determining divisibility. They perform arithmetic operations that do not provide information about remainders in division context. Therefore, using the modulus operator is the correct approach to check for even divisibility by any number, including 5.

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